The best answers to the question “How to truncate the time on a datetime object?” in the category Dev.
What is a classy way to way truncate a python
In this particular case, to the day. So basically setting hour, minute, seconds, and microseconds to 0.
I would like the output to also be a
datetime object, not a string.
date not a
datetime if you dont care about the time.
>>> now = datetime.now() >>> now.date() datetime.date(2011, 3, 29)
You can update a datetime like this:
>>> now.replace(minute=0, hour=0, second=0, microsecond=0) datetime.datetime(2011, 3, 29, 0, 0)
I think this is what you’re looking for…
>>> import datetime >>> dt = datetime.datetime.now() >>> dt = dt.replace(hour=0, minute=0, second=0, microsecond=0) # Returns a copy >>> dt datetime.datetime(2011, 3, 29, 0, 0)
But if you really don’t care about the time aspect of things, then you should really only be passing around
>>> d_truncated = datetime.date(dt.year, dt.month, dt.day) >>> d_truncated datetime.date(2011, 3, 29)
You cannot truncate a datetime object because it is immutable.
However, here is one way to construct a new datetime with 0 hour, minute, second, and microsecond fields, without throwing away the original date or tzinfo:
newdatetime = now.replace(hour=0, minute=0, second=0, microsecond=0)
Four years later: another way, avoiding
I know the accepted answer from four years ago works, but this seems a tad lighter than using
dt = datetime.date.today() dt = datetime.datetime(dt.year, dt.month, dt.day)
- When you create a
datetimeobject without passing time properties to the constructor, you get midnight.
- As others have noted, this assumes you want a datetime object for later use with timedeltas.
- You can, of course, substitute this for the first line:
dt = datetime.datetime.now()